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How to prove beyond-a-shadow-of-a-doubt that the Earth is flat, and not a sphere...
Position, somewhere on the Equator, a stationary reference "beacon" that sends out a signal in all directions -- or, at least - either East or West - with an angular range from North to South ( i.e. - 180 degrees with East / West in center - albeit, only the North 90 degrees will be significant ).
Position, on a ship / airplane, a directional receiver - such that, it can be determined with sufficient accuracy the angle ( relative to the Equator - or, directly behind ship / airplane ) the reference beacon is being detected.
Using a directional transmitter-receiver at both points would be even better.
Make sure that the signal - of whatever type - is of sufficient strength to reach a very long distance - and cannot be "blocked" by anything that might happen to come between the reference beacon and the ship / airplane.
As the ship / airplane moves away from the beacon, while staying on the equator:
~ If the Earth is a sphere, the signal will be lost soon enough because of the curvature of the earth; however, the angle from reference will never waiver from 0 degrees -- the beacon will always be directly behind the ship / airplane.
~ If the Earth is flat, the signal will be sustained for whatever distance it is capable of being detected; and, the detection angle will increase with the distance between the reference beacon and the ship / airplane.
Why? Because the ship / airplane will actually be following a circular path over the face of the Earth.
This will only work on the Equator - because, from a perspective regarding the angular part of the above suggested experiment - it is the only lattitude that is supposed to be a continual straight line all the way around the globe. And, that is why - if the results of the latter case are obtained - the Earth cannot possibly be a sphere.
Position, somewhere on the Equator, a stationary reference "beacon" that sends out a signal in all directions -- or, at least - either East or West - with an angular range from North to South ( i.e. - 180 degrees with East / West in center - albeit, only the North 90 degrees will be significant ).
Position, on a ship / airplane, a directional receiver - such that, it can be determined with sufficient accuracy the angle ( relative to the Equator - or, directly behind ship / airplane ) the reference beacon is being detected.
Using a directional transmitter-receiver at both points would be even better.
Make sure that the signal - of whatever type - is of sufficient strength to reach a very long distance - and cannot be "blocked" by anything that might happen to come between the reference beacon and the ship / airplane.
As the ship / airplane moves away from the beacon, while staying on the equator:
~ If the Earth is a sphere, the signal will be lost soon enough because of the curvature of the earth; however, the angle from reference will never waiver from 0 degrees -- the beacon will always be directly behind the ship / airplane.
~ If the Earth is flat, the signal will be sustained for whatever distance it is capable of being detected; and, the detection angle will increase with the distance between the reference beacon and the ship / airplane.
Why? Because the ship / airplane will actually be following a circular path over the face of the Earth.
This will only work on the Equator - because, from a perspective regarding the angular part of the above suggested experiment - it is the only lattitude that is supposed to be a continual straight line all the way around the globe. And, that is why - if the results of the latter case are obtained - the Earth cannot possibly be a sphere.
But what on earth makes you think this can only be carried out at the equator??
Lines of lattitude certainly complete their circles no matter what longitude. That's why the are called "parallels!" You can always travel due east or west.
Man, you guys really have absolutely no grasp of geometry, do you?
((case in point, Q.E.D.))
((sent from the nadir of a valley with no line-of-sight repeating tower, by satellite relay from a GPS-enabled cell phone, which is impossible on a disc-earth...))
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Not to give any credence to the 'flat earth theory' yet they say that the signal from cell phones are not transmitted by satellites but are received by cell towers which transmit the signal via land line the closest cell tower where the cell phone being called is located. The satellites merely locate the global position of the cell phone and routes the signal to the closest tower. The video link explains it.
https://www.youtube.com/watch?v=IJ9w3o5XTHc
However that is not to say that data can't be transmitted via satellites.
The original Telstar had a single innovative transponder that could relay data, a single television channel, or multiplexed telephone circuits. Source
How to prove beyond-a-shadow-of-a-doubt that the Earth is flat, and not a sphere...
So what is the width of this flat Earth?
How does a flat Earth have night and day when the sun is directly overhead?
The heaven of Genesis 1:1 is not the Heaven of 1:8. So is the earth in Genesis 1:1 the Earth of Genesis 1:10?
Yes, but cell phones with GPS enabled use satellite links to establish position, and most phones Internet browsers uses this location information whenever you use them. On GPS enabled phones ((like mine)) this location information is always being refined and used for a variety of things. It's a function that you can turn off, at least on Android, but it doesn't use cellular signals or wifi or any other data when enabled - location is determined by communicating directly with the network of global positioning satellites. This is far more accurate than tracking a data source or position from cell tower structure -- without the satellite use, phones could not use navigation apps.
The real salient point here is that in this flat disc earth sci-fi ssatellites are impossible. So cult members deny they exist, generally, even though there are so many everyday evidences of them, not the least of which is actually seeing them pass overhead, dozens per night, in an extraordinarily precisely predictable way, according to established physics of orbital mechanics.
"perspective" never makes half of an object disappear below the perceived horizon while the other half remains visible, without any apparent change in size.
that's not how "vanishing point" works.
if perspective was the reason that the sun appears to set at the close of the day, the sun would appear to get smaller and smaller and the distance between it and the horizon would become less and less -- but the sun itself would never actually appear to dip below that line.
and in the morning -- the sun would never actually appear to "rise" on a flat earth; it would always be above the horizon, though because of distance it would appear very small, and possibly appearing to be very close that line, it would always be above the line of the horizon.
so here's the experiment in the OP. the picture above. the "ship" that travels in a direction away from you every evening. if the earth is a globe, it should move in the sky in an arc determined by your latitude, and disappear below the horizon bit-by-bit at evening, reddening because of the greater density and volume of atmosphere that its light passes through slowing down its rays.
but if the earth is flat, the sun will just shrink in size at "sunset" time continually, never actually passing below the horizon, certainly not a portion of it below and a portion above, and all "night" long we should be able to find it traveling in a circle around us, at its lowest pint toward the north, so that it actually begins to rise in the north. and that, no matter where on earth you live: even at the equator, the sun should be seen travelling north all through the night, until midnight, when it is below the pole star, and then begins to rise until it reaches the east again, growing larger and larger.
that's not how "vanishing point" works.
if perspective was the reason that the sun appears to set at the close of the day, the sun would appear to get smaller and smaller and the distance between it and the horizon would become less and less -- but the sun itself would never actually appear to dip below that line.
and in the morning -- the sun would never actually appear to "rise" on a flat earth; it would always be above the horizon, though because of distance it would appear very small, and possibly appearing to be very close that line, it would always be above the line of the horizon.
so here's the experiment in the OP. the picture above. the "ship" that travels in a direction away from you every evening. if the earth is a globe, it should move in the sky in an arc determined by your latitude, and disappear below the horizon bit-by-bit at evening, reddening because of the greater density and volume of atmosphere that its light passes through slowing down its rays.
but if the earth is flat, the sun will just shrink in size at "sunset" time continually, never actually passing below the horizon, certainly not a portion of it below and a portion above, and all "night" long we should be able to find it traveling in a circle around us, at its lowest pint toward the north, so that it actually begins to rise in the north. and that, no matter where on earth you live: even at the equator, the sun should be seen travelling north all through the night, until midnight, when it is below the pole star, and then begins to rise until it reaches the east again, growing larger and larger.
What does it matter whether the earth is flat or round? It's all gonna get destroyed soon anyway. Surely there are more important things to worry about.. Like the shortage of chocolate in my house. lol
lol
Now to the very important thing. Are those round chocolate covered cherries,or flat chocolate thin mints?
Blesdings
Bill
How to prove beyond-a-shadow-of-a-doubt that the Earth is flat, and not a sphere...
...
~ If the Earth is a sphere, the signal will be lost soon enough because of the curvature of the earth; however, the angle from reference will never waiver from 0 degrees -- the beacon will always be directly behind the ship / airplane.
~ If the Earth is flat, the signal will be sustained for whatever distance it is capable of being detected; and, the detection angle will increase with the distance between the reference beacon and the ship / airplane.
Why? Because the ship / airplane will actually be following a circular path over the face of the Earth.
This will only work on the Equator - because, from a perspective regarding the angular part of the above suggested experiment - it is the only lattitude that is supposed to be a continual straight line all the way around the globe. And, that is why - if the results of the latter case are obtained - the Earth cannot possibly be a sphere.
...
~ If the Earth is a sphere, the signal will be lost soon enough because of the curvature of the earth; however, the angle from reference will never waiver from 0 degrees -- the beacon will always be directly behind the ship / airplane.
~ If the Earth is flat, the signal will be sustained for whatever distance it is capable of being detected; and, the detection angle will increase with the distance between the reference beacon and the ship / airplane.
Why? Because the ship / airplane will actually be following a circular path over the face of the Earth.
This will only work on the Equator - because, from a perspective regarding the angular part of the above suggested experiment - it is the only lattitude that is supposed to be a continual straight line all the way around the globe. And, that is why - if the results of the latter case are obtained - the Earth cannot possibly be a sphere.
... There are no satellites. ....
There are no satellites. ( actually "orbiting" in space )...
There are no satellites. ( actually "orbiting" in space )...
